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FAST Protocol
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Re: Identify Frame lenght in FAST UDP packet
janaka Sooriyaarachchi / MillenniumIT 8 Feb 2012 9:52PM ET Hi,
In the Case 1,
Very first bit also have a stop bit.
So your message length is 113. That contains in a single byte
But in case 2,
you need to take 2 bytes,
00000001 10001011
After removing stop bits,
0000001 0001011
Then convert that value to decimal
00000010001011 = 139
now your message length is 139.
> Hi Janaka
>
> Binary feeds received have following value in first four bytes.
> What will be stop bit here to find message length here ?
>
> case 1.
>
> Uncompressed binary data received
>
> F1 DE 00 83
> 11110001 11011110 00000000 10000011
>
>
>
> Removing first bit and converting to integer value
>
> 1110001 11011110 - 0000011
>
> Integer Value
>
> 113 94 3
>
> ************************************************************************
>
>
> Case 2
>
> Uncompressed binary data received
>
>
> 01 8B DE 00
> 00000001 10001011 11011110 00000000
>
>
> Removing first bit and converting to integer value
>
> - 0001011 1011110 -
>
> Integer Value
>
> - 11 94 -
>
>
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> > frame size also a integer value, So you can use integer encoding/ decoding method to resolve the value and you can identify the field termination by stop bit.
> >
> >
> > > Hi
> > >
> > > I am receiving UDP packet in following manner
> > >
> > > |frame size(1)|msg(1)|frame size2|msg(2)|...|frame size(i)|msg(i)|
> > > =================================================================
> > > UDP PACKET N
> > >
> > > How to identify frame length so that I can find size of msg(1)...consequently of msg(2)......msg(3)....
> > >
> > > Frame size usually the first byte but it can be up to 4 bytes of uncompressed data received.How to identify when it's more than 1 byte?
> > >
> > > Thanks
> > >
> > > Himanshu
Re: Identify Frame lenght in FAST UDP packet janaka Sooriyaarachchi / MillenniumIT 8 Feb 2012 9:52PM ET |